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08 · 18 min

Heating

Specific heat capacity, latent heat, and why temperature is not heat.

E = mcΔθ

The idea

Temperature is a measure of how hot something is, linked to the average kinetic energy of its particles. Heat, or heating, is energy transferred because of a temperature difference. A bath of lukewarm water can store more thermal energy than a cup of boiling water.

The energy to change the temperature of a mass is E = mcΔθ. c is the specific heat capacity: how many joules warm 1 kg by 1 °C. For water, c is 4 200 J/kg °C. A heater supplies energy at E = Pt, and if nothing escapes, the two expressions match.

Changing state at constant temperature takes energy too. E = mL, where L is the specific latent heat. That is why a kettle that has reached 100 °C keeps taking energy while the water turns to steam, without the temperature rising.

Formulas

Specific heat capacity

E = mcΔθ

A temperature change with no change of state. Δθ is in °C or K; the difference is the same.

E
energy
J
m
mass
kg
c
specific heat capacity
J/kg °C
Δθ
temperature change
°C

Specific latent heat

E = mL

Melting or boiling, with no temperature change. L is larger for vaporising than for melting.

E
energy
J
m
mass that changes state
kg
L
specific latent heat
J/kg

Energy from a heater

E = Pt

Pair this with E = mcΔθ when a heater warms a substance and losses are ignored.

E
energy
J
P
power
W
t
time
s

Worked examples

Warming water with a heater

0.20 kg of water is warmed from 20 °C to 100 °C. c = 4 200 J/kg °C. How much energy is needed, and how long does an 800 W heater take if no energy escapes?

Mass
0.20 kg
Temperature change
80 °C
Heater
800 W

Try it on paper first. Then open the working one step at a time.

    Melting ice at 0 °C

    How much energy melts 0.050 kg of ice at 0 °C? The specific latent heat of fusion of ice is 3.34 × 10⁵ J/kg. The water produced is still at 0 °C.

    Mass
    0.050 kg
    L
    3.34 × 10⁵ J/kg

    Try it on paper first. Then open the working one step at a time.

      Checks

      2.0 kg of aluminium (c = 900 J/kg °C) is warmed by 15 °C. How much energy is transferred, in joules?

      2 100 J of energy warms some water by 1.0 °C. c = 4 200 J/kg °C. What is the mass of the water, in kg?

      A 100 W heater runs for 40 s in 0.10 kg of water. c = 4 200 J/kg °C. Ignore losses. What is the temperature rise, to 1 decimal place, in °C?

      Which statement is correct?

      Easy places to lose a mark

      • Using the final temperature instead of the change.
      • Using E = mcΔθ while a substance is melting or boiling. The temperature is not changing.
      • Forgetting that a real heater also warms the beaker and the air, so the liquid does not get all of Pt.

      Practical

      Heat can

      Predict the temperature rise from a heater running for 60 s.